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3x^2+11x-484=0
a = 3; b = 11; c = -484;
Δ = b2-4ac
Δ = 112-4·3·(-484)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-77}{2*3}=\frac{-88}{6} =-14+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+77}{2*3}=\frac{66}{6} =11 $
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